[最新] 3x 2y=2xy 1/x 2/y=7/6 278597-3x 2y 2xy 1/x 2/y 7/6
2 Integrating leads to y=v^22, which is y=(x^2/y^2)2 but in my book the answer comes with an additional factor of two in the answer so the right answer should be y=(x^2/2y^2)2 # (partial f) / (partial x) = 6x^2y^210x# # (partial f) / (partial y) = 2xy2y# So our critical equations are # 6x^2y^210x = 0# # 2xy2y = 0# From the second equation we have # 2y(x1) = 0 => x=1,y=0# Subs #x=1# into the First equation and we get # 6y^210 = 0 => y^2=4=>y=2# Subs #y=0# into the First equation and we get 3x 2y 2xy 1/x 2/y 7/6